$x^2+4xy+4^2$
$16+2$
$-6-\left(2-3\right)$
$-2\cdot3-6$
$\int\left(\left(x+3\right)\left(x-5\right)^5\right)dx$
$\int_0^{10}3xdx$
$-14\frac{2}{3}>-16$
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