$\int\left(\sqrt{\sec^2\left(x\right)+1}\right)\left(\tan\left(x\right)\right)dx$
$-\frac{1}{2}+3-5+\frac{3}{2}$
$\frac{1-3x\left(2x^2+3x-5\right)}{x-1}$
$5+8\left(x+10\right)$
$4ab^2+6ab^2-6a^2b$
$6\cdot\left(2x+3y\right)^2$
$\int\frac{x}{\sqrt{1-4x^4}}dx$
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