$\int\frac{21x^2}{4\left(x^3+5\right)^{\frac{5}{4}}}dx$
$\left(r-6^2\right)$
$\left(6t^3-8r^2\right)^2$
$\int8xsec^2\left(x\right)tan\left(x\right)dx$
$11ab^5\cdot3a^2b^3c^9$
$\frac{\cos\left(x\right)}{\sec x-\text{tgx}}=1+\sin$
$-49+25u^2$
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