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$\lim_{x\to\infty}\left(\frac{\sqrt{1+4x^2}}{4+x}\right)$

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Other solved exercises

$9x^2-8x+4$

$-12\cdot5+4$

$\frac{1}{5}x+2$

$4\left(10-3\right)+5\left(15+6\right)$

$\int\:\frac{\left(5x\right)}{x+1\:}dx$

$25+\left(18+13\right)+16+\left|56+12\right|+\left|65+32\right|$

$\left(11y-7\right).\left(6y+2\right)$
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