$8x^6+7x^3-1$
$\int_6^3\left(e^u\right)du$
$\lim_{t\to0}\left(\frac{\left(e^{2t}-1\right)}{\sqrt{te}}-e^2\right)$
$\left(8x-1\right)\left(8x+1\right)$
$\left(6mx+4ny\right)^2$
$3+2c=11$
$\left(3^2+3\right):\left(-3\right)$
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