$6\left(x-3\right)=42$
$\left(2u+3q\right)^2+8\left(2u+3q\right)+16$
$x\cdot0$
$10x+2y-2xy^2-2x^2y$
$\sqrt{a}+2\sqrt{3b}-\sqrt{c}+3\sqrt{3b}$
$3\left(-5n+8\right)\:-2n\left(2n+6\right)$
$\frac{3^7}{3^5}$
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