$\frac{1}{sin\left(x\right)}=\frac{1}{3}$
$\frac{dy}{dx}=2-x-x^3$
$\frac{x^3+5x-1}{x+3}$
$5x^2\cdot3xy\cdot2x-6x^3\cdot3x\cdot2y$
$40,131\left(8\right)$
$4cos2x+4cos4x=0$
$\frac{4x^3-2x^2+5x+5}{x^2-2}$
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