$\left(1-\frac{sin^2x}{16}\right)^{\frac{1}{2}}$
$x^2-22-121$
$3^5-4$
$16x-x$
$\frac{x^3}{1+3x^2}=3x^2$
$18b-3z=3$
$\frac{1-\cos\:\left(4\theta\:\right)}{2\theta\:\:sin3\theta\:}$
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