$\frac{x+3}{x-2}\ge2$
$-20-\left(-18\right).$
$\left(tu\right)^{\frac{3}{4}}$
$x^2-28x+115$
$9m^2+3mn+36n^2$
$\frac{x}{x-1}\ge\frac{1}{x-1}$
$\lim_{x\to\infty}\left(\frac{-17x-e^{9x}}{5x^2+7x-5}\right)$
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