$\sqrt{\frac{x^8}{y^6}}$
$m^{12}+1$
$\frac{dx}{dt}=3xt^3$
$2-3-\left(-8\right)+9$
$\frac{4\left(h^{4}\right)^{4}}{12h}$
$\left(4x^3-5\right)^2$
$\frac{2x^3+x-6}{x+2}$
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