$3\cdot3^2\cdot3^{-3}\cdot3^5\cdot3^5$
$3cosa+3sina=3$
$5\cdot1-7-1-7+8\cdot4$
$\left(6\cdot10^3\right)\left(2\cdot10^5\right)$
$7.95+17.4j=-11.52+17.4j$
$\left(-127\right)\left(-4\right)$
$\frac{\left(x^3\right)}{x+1}x^2+5x$
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