$\sqrt{15y^3}$
$\int\frac{\left(2x-4\right)}{x+3}dx$
$\int\left(\frac{1}{x^2\sqrt{64-x^2}}\right)dx$
$\left(x+y^3\right)+6xy^2y'=0$
$\frac{x^{-3}y^{-1}}{\left(2yx^4\right)^2}$
$4988.78+456.98$
$\frac{1}{5-y}dy=cos\left(x\right)dx$
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