$\frac{6x+12}{3x-6}$
$\lim\:_{x\to\:\infty\:}\frac{\left(4^x+3x\right)}{x^2-4^x}$
$9x+2y-3z+9x+6y-8z$
$-4x+7y=28$
$\left(11c^2+3\right)^2$
$\int\left(12x\:ln\:7x\right)dx$
$\int x\sqrt{1-\left(x-1\right)^2}dx$
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