$cos\:t\:=-\frac{4}{5}$
$\frac{\left(cos^2x\right)}{\left(sin2x\right)}=\frac{\left(cotx\right)}{2}$
$x^2-6x\ge-8$
$x\frac{d^2}{dx^2}\left(y\right)+y=0$
$8xy+7xy-xy+3xy-xy$
$x-3=4$
$4z+8z$
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