$\left(100a+2b\right)\left(2a-3b\right)$
$-5\cdot2+11$
$-3\left(2d+4\right)-5\left(d-6\right)$
$\lim_{x\to1}\left(\frac{2x\:+\:3}{x^2\:-1}\right)$
$3x+1>10$
$\frac{2}{x}=\frac{5}{x^2-4}$
$\frac{d^3}{dx^3}\left(x^5+3x^{-2}+4x\right)$
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