$\lim_{x\to\infty}\left(8x+1\right)^{\frac{1}{x}}$

$3x^2-4x+2=0$

$\frac{-4x^5-3}{x^3}$

$\ln\left(x+5\right)=\ln\left(x-1\right)-\ln\left(x+1\right)$

$csc^{\left(4\right)}x-cot^{\left(4\right)}x=csc^{\left(2\right)}x+cot^{\left(2\right)}x$

$\frac{dy}{dx}=\frac{10+y^2}{2xy}$

$\sqrt{6^6}$