$\int x^4.\arccot\left(x\right)xdx$
$\frac{3u+4}{-u-3}$
$x+y=41$
$\left(d^2-1\right)y=3x^4-5x+1$
$\int_0^{0.5}\left(\frac{1}{\left(x-1\right)}\right)dx$
$1x^2-3x+28$
$6x+3<1$
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