$\frac{d}{dx}\left[\sqrt{5+3lnx}\right]$
$x^5+10x^4-15x^3$
$\left(1+\tan^2x\right)\cot^2x=\sec^2\cot^2$
$4x^2+1x+49$
$-\frac{5}{6}a^2b+\frac{1}{8}a^2b$
$5+2.75$
$2\left(x-2\right)=x-6$
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