$4\left(5z\right)$

$\lim_{x\to\infty}\left(\frac{ln\:1+\frac{8}{x}}{\frac{1}{6x}}\right)$

$\int\frac{4x^{2}+3x+14}{\left(x+1\right)\left(x^{2}+4\right)}dx$

$a^2-22a+120$

$9x^2+42x+25$

$\frac{d}{dx}y=\tan\frac{1}{x}$

$\left(7x^3+y^2-4x+5\right)-\left(32x^3+3x^2-8x+10\right)$