$2\cdot a\cdot a$
$3-3x>-11$
$16x^2+4x+8$
$\sqrt{3}x^2+6x+3\sqrt{3}$
$\left(5x+4m\right)^2$
$\left(3a\:+\:2c\right)^3$
$\frac{h^{2}-6h-16}{4h^{2}-16}$
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