$\frac{\left(\left(x\cos\left(t\right)+h\right)-h\right)^2}{x^2}$
$\:-a+b+2b-2c+3a+2c-3b-a+3a$
$sec=\frac{3}{2}$
$tan\:x\:+\:cot\:x\:=sec\:x\cdot\:sen\:x$
$3x^2-2x+3<0$
$-4x+13=6x-7$
$x^2+2x=5$
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