$\sqrt[3]{\left(1.41b+3.92\right)^2}$
$x^4+x-2$
$-\frac{3}{2}y+\frac{1}{4}y^{2}$
$4x^3+2x^2-3x+2-5x^3+2x^2-4x-2$
$\left(5x^2+17x-40\right)-\left(x^2+4x+4\right)$
$\int\:\frac{x}{x+4}dx$
$-\:x^2-4x-5<0$
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