$\left(\frac{2}{3}x\:+\frac{1}{4}y\right)^3$
$\tan^2b=1$
$-3z-\left(-z-2\right)=-4z+2$
$3ab-2a\left(b-2\right)$
$xy=2x^2+10x+12$
$\frac{-2h^2+h}{\left(h^2+1\right)\left(h\right)}$
$3a+7-11-9a$
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