$2x\cdot7\cdot2\cdot\:4x$
$\lim_{x\to0}\left(\frac{2-2\cos\left(x\right)}{6x}\right)$
$x\left(2\right)-4x+4$
$\sqrt[2]{x}+5=7$
$9\left(7\right)+\left(-6\right)\left(-2\right)\left(-4\right)$
$\frac{1}{\sqrt{5+2x}}$
$-72+2$
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