$\frac{1}{1-\sin^2\left(x\right)}=\tan^2\left(x\right)\left(1+\cot^2\left(x\right)\right)$

$\sqrt[5]{a^2}\cdot a^{\frac{1}{2}}$

$\lim_{x\to-4}\left(\frac{x^2-16}{2x-8}\right)$

$-0.24\left(-3.25+5.65\right)$

$\int\left(\frac{2x}{\sqrt{x^2-4x+13}}\right)dx$

$\int_{-1}^1-12xdx$

$\frac{dy}{dx}=\frac{\left(3-x\right)^2}{y}$