$49z^2-25=0$
$4cos^2\left(\frac{3\pi}{2}\right)-3sin^2\left(\frac{3\pi\:}{2}\right)$
$\:\left(8x-7\right)\left(4x+10\right)\cdot$
$5.29a^2+23.46ab+26.01b^2$
$10\left(2m-7\right)$
$sin2x-cos2x=1$
$\left(x-12\right)\left(x-4\right)$
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