$\tan\left(x\right)^2+\sec\left(x\right)^2-3\:=\:0$
$\frac{dy}{dx}=y^5e^x$
$\cos^2x+4\cos x=0$
$\frac{x^2+5x+2}{x+1}$
$x\left(\frac{dy}{dx}\right)-y-3x^2=0$
$\sqrt{64x^4y^{22^2}}$
$1+7-4$
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