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Find the limit of $\frac{1-\cos\left(x\right)}{x^2}$ as $x$ approaches 0

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Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Algebra 2 - Determine and describe the discriminant 5x^2 - x -1 = 0

https://www.youtube.com/watch?v=F3eTBxCnzvI

Calculus - Evaluating a limit by rationalizing the radical, lim(x tends to 0) (sqrt(x + 1) - 1)/x

https://www.youtube.com/watch?v=v8dIvXm03dw

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Calculus - Learn how to evaluate a limit by factoring, lim(x tends to -1) (x^2 - 5x - 6)/(x + 1)

https://www.youtube.com/watch?v=-nTo1qgNDLE
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Tips on how to improve your answer:

$\lim_{x\to 0}\left(\frac{1-\cos\left(x\right)}{x^2}\right)$

Main topic:

Limits

Related Formulas:

7. See formulas

Time to solve it:

~ 0.06 s