$\left(5x^2+8y^5\right)^3$
$\frac{\left(2x+1\right)}{\left(x+3\right)}\ge1$
$6a-3x$
$1-4sin^2x=4cos^2x-3$
$\int\left(\frac{12}{\left(4x-9\right)^4}\right)dx$
$\left(x^3-x^2+6\right)+\left(5x^2-4x+6\right)$
$\left(3x^3y^2-5x^2\right)^3$
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