$\left(1-3x\right)^5$
$\int\:a\:\:dx$
$36a^2b^6-64$
$\int\frac{4x^2+6x+11}{\left(x^2+1\right)\left(x+4\right)}dx$
$\left(6x^2-m^2\right)^2$
$\left(13a-3\right)\left(13a+3\right)$
$\frac{dy}{dx}-y=\frac{y}{\left(x+1\right)}$
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