$\frac{ab^3}{b^2}$
$12 \cdot 3 + 18 : ( - 2 + 8 )$
$3-7x\leq -4$
$\frac{6}{1-\sin\left(x\right)}+\frac{6}{1+\sin\left(x\right)}=12\sec^2\left(x\right)$
$2x^4-72y^4r$
$ydy=x^2dx$
$-12\left(-3\right)$
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