$\left(-2a+1\right)^3$
$\left(x+\frac{1}{4}\right)\left(x+\frac{3}{4}\right)$
$3x+5>5x-2$
$\left(-3\right)+\left(-5\right)-\left(-6\right)+\left(+4\right)$
$2-4p=-3p-4$
$\frac{5\left(0\right)^2}{28\left(11\right)}$
$\frac{88}{11}$
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