$\frac{d}{dx}\left(3e^{x^2}\right)$
$7\cdot\left(-1\right)-\left(-4\right)\cdot3$
$x-8=-4$
$\int te^{14t}dt$
$\left|\left(-2x\right)\left(x^{-3}\right)\right|^{-2}$
$8+3\cdot5^2-7^2$
$\int_0^xtdt$
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