$\frac{\left(2x+2\right)^n}{n}$
$ty'-y=\left(t+1\right)^2$
$2\sin\left(x\right)-1=-\sin\left(x\right)^2-2$
$\sqrt{-16}+\sqrt{-36}$
$\left(3x^2\right)\left(-\frac{2}{3x^3}\right)\left(4x^2\right)$
$\frac{1}{x-1}+\frac{1}{2-3x+x^2}$
$y^2-8y+15$
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