$\frac{sin^2x-2sinx+1}{sinx-1}+1=sinx$
$2x-5>-3+x$
$x-5>2x-6$
$i=2\left(1-e^{-3t}\right)$
$x+x+y$
$\lim_{x\to\infty}\frac{\sqrt{x^2+4}}{x+x^2}$
$\left(3+x\right)^2=9+x^2+8x$
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