$\lim_{x\to0}\left(1+2x^2\right)$

$-7cos^2x=7sin2x$

$\lim_{x\to\infty}\left(\frac{5-5cos2x}{4-4tan2x}\right)$

$\frac{\sqrt{ln}\left(x\right)}{ln\sqrt{x}}=3$

$4\left(2\right)^5-4\left(2\right)^4+10\left(2\right)^2-\left(2\right)-6$

$\cot w-\frac{\csc^{2}w}{\cot w}$

$\sqrt{0.1}$