$m^2+2m-15=0$

$2x<5$

$\frac{tan\left(x\right)}{sin\left(2x\right)}=\:\frac{1}{2\left(1\:+\:cot^2\left(x\right)\right)}$

$\int\left(\frac{e^{9x}}{1-e^{9x}}\right)dx$

$1+\left(-3\right)\left(4\right)$

$3x^2+2x-1=0$

$\left(2y-\left(\frac{3}{2}\right)\right)^2-\left(y-4\right).\left(y+\left(\frac{1}{2}\right)\right)-2y^2$