$\left(x^5+2x^3\right)^2$
$\frac{-20a^2b^2}{8ab}$
$x\left(x+8\right)=0$
$\int\frac{x+3}{\sqrt{x^2-4}}dx$
$-3+1+0+-2+-1$
$21\cdot35$
$\frac{2}{x^2-1}=\frac{1}{x-1}$
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