$\int7e^{8x}dx$
$\frac{\tan\left(x\right)+\cot\left(x\right)}{\sec\left(x\right)^2}=\cot\left(x\right)$
$\log\left(2x+1\right)=\log\left(15\right)$
$y^{\prime}=-\cos\frac{1}{2}x$
$\ 2xy-10x+\left(x^2-4\right)\frac{dy}{dx}=0$
$\lim_{x\to3}\left(4x^3+8x^2-2x+1\right)$
$4x+1>10$
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