$\lim_{x\to\infty}\left(\frac{e^x-x-1}{cos\left(2x\right)}\right)-1$

$6\sin^2\left(x\right)-7\cos\left(x\right)-1=0$

$\left(6xy+2z\right)^{3}$

$9=1+2x$

$x^2+19\ge9x-x^2$

$\csc\left(x\right)\sin\left(x\right)\sec\left(x\right)=\frac{1}{\cos\left(x\right)}$

$4b^2+9d^2-12bd$