$\left(9^4\right)^6$
$2x^2-7x=-3$
$\frac{dy}{dx}=\frac{2x+5y}{x}$
$\frac{x^4-0x^3-3x^2+2x-5}{x+3}$
$x'=\frac{x}{1+t}$
$\frac{-2}{\sqrt{x}}+\frac{\sqrt[5]{x}}{3}$
$3\:2\:x\:5\:+7\:x\:4$
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