$\left(4x+1\right)\left(6x+5\right)$
$\frac{18y^4}{-2y^3}$
$y'+5^{x+y}=0$
$\left(-2a^3b^5\:m^{-3}x^{-2}\right)^2$
$\int8\cos\frac{4x}{3}dx$
$sen^2\left(0\right)$
$\left(-1\right)+\left(+8\right)+\left(-68\right)$
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