$sen\left(x\right)=0.6$
$5.\:\left(x\:-\:11\right)\:\left(x\:+\:10\right)$
$\frac{dy}{dt}=t^{\frac{3}{2}}y^5$
$-6x\:-2y+8x+x-9$
$\frac{4}{x\:-\:1}=0$
$\frac{4x^3+8x^2}{x+2}$
$sen^2\left(x\right)+sen^2\left(x\right)\left(\frac{sen^2\left(x\right)}{cos^2\left(x\right)}\right)$
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