$\left(7g^5\right)^{-2}$
$y'=y^2-9$
$15+\left(3-\left(-11-\left(13+14\right)-7\right)\right)$
$\left(z^2+41\right)\cdot\left(z^2+10\right)$
$\sqrt{x^2\:+\:\frac{1}{\sqrt{2}}x^4\:+\:\frac{1}{3}x^6}$
$\sqrt[3]{10.648}$
$\frac{1}{2+4x}$
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