$\lim_{x\to\infty}\frac{2x^4+x^2+5}{3x^5+x^3-x}$
$\ln\left(x+1\right)^2=2$
$\left(3x^{2}+2x-2\right)+\left(-2x^{2}+5x+5\right)$
$\frac{8}{5}=\frac{32}{x}\:$
$70x^4y^5+35x^4y^3+20x^7y^4$
$2x^2+4x+49$
$\frac{dy}{dx}+\frac{4}{5}xy=3$
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