$\frac{\left(2x^5-5x^4+6x^3+4x^2-11x\right)}{\left(1-3x+2x^2\right)}$
$3x^5-x^3$
$\log x^2=\log_e\left(4\right)$
$7-3\cdot1$
$+\left(8-5\right)-7+2\left(-2\right)-\left(5-4\right)$
$\lim_{x\to\infty}\left(1+5x^3\right)^{\frac{4}{x}}$
$\frac{d^2y}{dx^2}\left(9x^2+4x\right)$
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