$\int\left(x-3\right)\cos\left(x+2\right)dx$
$4\left(x+1\right)-6x>4$
$\int\frac{2x+3}{\left(x^3-2x^2+x\right)}dx$
$\left(x-7\right)\left(2x+8\right)$
$4.75+27$
$\int10x\:e^x\:dx$
$\frac{\left(x^2+2xy-1\right)}{xy^2+3};\:x=-1;\:y=3$
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