$\frac{16}{4}\left(1\right)\left(2\right)^2\left(-1\right)^3$
$27^2$
$-\frac{2}{2}+6-1$
$3z^7-7z^3+21z^2$
$y=\left(x+3\right)\left(x+1\right)$
$\int_0^6xdx$
$\frac{q^2q^5}{q^7}$
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