$3\left(7\right)-8$
$\int\frac{x^3}{x}-\frac{6x}{x}dx$
$5a-3a-19=1$
$6x^3+5x^2-19x-10$
$\frac{1}{25}+\frac{x^2}{3}-\frac{2x^4}{36}$
$\left(5x+8y+3xy\right)^2$
$\int\frac{8}{x^2-4}dx$
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