$\left(3x^2-8y^3\right)^2$
$x^3+2y\frac{dy}{dx}=0$
$\lim_{x,y\to-2,3}\left(\frac{e^{2y}\sin\left(3x\right)}{x^2}\right)$
$3x^4+0x^3-10x^2+0x+3$
$\left(6x+2\right)\left(60x+4\right)$
$-5-\left(-7\right)8-1014+\left(-6\right)$
$\left(mna+1\right)\left(mna-1\right)$
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